The solution set for x(x+2)^2(x 1)^5(2x 3)(x 3)^4>or equal to 0 is given by x belongs to [a,b] union [c,infinity) then the value of a+B+C=______
![Solve the equationsdfrac{3x^4 + x^2 - 2x - 3}{3x^4 - x^2 + 2x + 3} = dfrac{5x^4 + 2x^2 - 7x + 3}{5x^4 -2x^2 + 7x - 3} Solve the equationsdfrac{3x^4 + x^2 - 2x - 3}{3x^4 - x^2 + 2x + 3} = dfrac{5x^4 + 2x^2 - 7x + 3}{5x^4 -2x^2 + 7x - 3}](https://haygot.s3.amazonaws.com/questions/1568198_1741927_ans_28cdc37f172946b29c708f422da4a73a.jpg)
Solve the equationsdfrac{3x^4 + x^2 - 2x - 3}{3x^4 - x^2 + 2x + 3} = dfrac{5x^4 + 2x^2 - 7x + 3}{5x^4 -2x^2 + 7x - 3}
![2x-3/5 + x+3/4 = 2x+3/4 solve for x - Maths - Linear Equations in Two Variables - 3170223 | Meritnation.com 2x-3/5 + x+3/4 = 2x+3/4 solve for x - Maths - Linear Equations in Two Variables - 3170223 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/2315393/2012_10_30_14_28_23/mathmlequation405851204522417304.png)